(x+5)^2=(1-x)(1+x)+24

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Solution for (x+5)^2=(1-x)(1+x)+24 equation: 



(x+5)^2=(1-x)(1+x)+24

We move all terms to the left:

(x+5)^2-((1-x)(1+x)+24)=0

We add all the numbers together, and all the variables

(x+5)^2-((-1x+1)(x+1)+24)=0

We multiply parentheses ..

-((-1x^2-1x+x+1)+24)+(x+5)^2=0



We calculate terms in parentheses: -((-1x^2-1x+x+1)+24), so:

(-1x^2-1x+x+1)+24

We get rid of parentheses

-1x^2-1x+x+1+24

We add all the numbers together, and all the variables

-1x^2+25

Back to the equation:

-(-1x^2+25)



We get rid of parentheses

1x^2+(x+5)^2-25=0

We add all the numbers together, and all the variables

x^2+(x+5)^2-25=0

We move all terms containing x to the left, all other terms to the right

x^2+(x+5)^2=25

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